Find the equation of the circle having center at (1,2) and which
touches `x+y=-1`.
Text Solution
Verified by Experts
The centre of the circle is `C (2,3)`. Also, line `x+y-1=0` is tangent to the circle. Hence, the radius of the circle is the perpendicular distance of centre from the tangent. Therefore, radius `r=CP=(|2+3-1|)/(sqrt(1^(2)+1^(2)))=2sqrt(2)` Hence, the equation of circle is `(x-2)^(2)+(y-3)^(2)=8`
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