Find the equation of the circle which passes through (1, 0) and (0, 1)
and has its radius as small as possible.
Text Solution
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The radius will be miniumum if the given points are the endpoints of a diameter. Then, the equation of the circle is `(x-1)(x-0)+(y-0)(y-1)=0` or ` x^(2)+y^(2)-x-y=0`
Find the equation of a sphere which passes through (1,0,0)(0,1,0)a n d(0,0,1), and has radius as small as possible.
The equation of the circle passing through (2, 0) & (0, 4) and having the minimum radius is
The equation of the circle passes through the point (0, 4), (0, 0) and (3, 0) is
Find the equation of the circle with centre at (0,0) and radius r .
Find the equation of the sphere which passes through (1,0,0),(0,1,0) and (0,0,1) and whose centre lies on the plane 3x-y+z=2.
Find the equation of a circle which passes through (0, -3) and (3, -4) and the centre lies on the straight line 2x - 5y + 12 = 0.
Find the radius of the circle passing through (6,0), (0,8) and origin .
Find the equation of the circle passing through (6, -5) and having centre at (3, -1).
Find the equation to the circle which passes through the point (2,-2),(3,4) and has its centre on the line 2x+2y=7. Find the centre and radius.
Find the equation of the circle which passes through (1, 1) and cuts orthogonally each of the circles x^2 + y^2 - 8x - 2y + 16 = 0 and x^2 + y^2 - 4x -4y -1 = 0
