Find the parametric form of the equation of the circle `x^2+y^2+p x+p y=0.`
Text Solution
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The equation of the circle can be rewritten in the form `(x+(P)/(2))^(2)+(y+(p)/(2))^(2)=(p^(2))/(2)` Therefore, the parametric form of the equation of the given circle is `x=-(p)/(2)+(p)/(sqrt(2))cos theta` `=(p)/(2)(-1+sqrt(2)cos theta)` and `y= -(p)/(2)+(p)/(sqrt(2)) sin theta` `=(p)/(2)(-1+sqrt(2)sin theta)` where `0 lethetalt2pi`
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