If the two lines `a_1x + b_1y + c_1 = 0` and `a_2x + b_2y + c_2 = 0` cut the co-ordinates axes in concyclic points. Prove that `a_1a_2 = b_1b_2`
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Line `a_(1)x+b_(1)y+c_(1)=0` meets he axes at points `P(-(c_(1))/(a_(1)),0)` and `Q(0,-(c_(1))/(b_(1)))` Line `a_(2)x+b_(2)y+c_(2)=0` meets the axes at points `R(-(c_(2))/(a_(2)),0)` and `S(0,-(c_(2))/(b_(2)))` Since points P,Q,R and S are concyclic , we have `OP xx OR=OQ xx OS` , where O is origin. `implies |(-(c_(1))/(a_(1)))(-(c_(2))/(a_(2)))|=|(-(c_(1))/(b_(1)))(-(c_(2))/(b_(2)))|` `implies |a_(1)a_(2)|=|b_(1)b_(2)|`
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