Find the equation of the tangent at the endpoints of the diameter of
circle `(x-a)^2+(y-b)^2=r^2`
which is inclined at an angle `theta`
with the positive x-axis.
Text Solution
Verified by Experts
Diameter makes an angle `theta` with x-axis. So, the slope of diameter is `tan theta` Therefore, slope of tangent is `-cot theta`. Hence, equations of tangents having slope `'-cot theta'` are given by `y-b=- cot theta (x-a)+- r sqrt(1+cot^(2)theta)` or `cos theta (x-a)+sin theta(y-b)= +- r`
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