Find the equation of the normal to the circle `x^2+y^2-2x=0`
parallel to the line `x+2y=3.`
Text Solution
Verified by Experts
Slope of given line is `-(1)/(2)`. So, slope of normal is `-(1)/(2)`. Normal passes through the centre of the circle. Here, centre is (1,0). Therefore, equation of normal is `y=0=-(1)/(2)(x-1)` or `x+2y-1=0`
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