Find the equation of radical axis of the circles `x^(2)+y^(2)-3x+5y-7=0` and `2x^(2)+2y^(2)-4x+8y-13=0`.
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We have circles `x^(2)+y^(2)-3x+5y-7=0` (1) and `2x^(2)+2y^(2)-4x+8y-13=0` (2) Equation of radical axis of the two circles can be obtained by subtracting the equation of one circle from that of the other in such a way that term `x^(2)` and `y^(2)` gets cancelled out. So, multiplying equation (1) by 2 and then subtracting equation (2) from it, we get ,brgt `-2x+2y-1=0` or `2x-2y+1=0`
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