The angle at which the circle `(x-1)^2+y^2=10 and x^2+(y-2)^2=5` intersect is
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Here, `C_(1)-=(1,0` and `r_(1)=sqrt(10)`. And `C_(2) -= (0,2)` and `r_(2)=sqrt(5)`. Also, `C_(1)C_(2)=sqrt(1^(2)+2^(2))=sqrt(5)` If circles intersect at an angle `theta`, then `cos theta =((C_(1)C_(2))^(2)-r_(1)^(2)r_(2)^(2))/(2r_(1).r_(2))=(5-10-5)/(2.sqrt(10).sqrt(5))=-(1)/(sqrt(2))` `:. theta =(3pi)/(4)`
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