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int(sin((pi)/(4)-x)dx)/(2+sin2x)=A tan^(...

`int(sin((pi)/(4)-x)dx)/(2+sin2x)=A tan^(-1)(f(x))+B`, where A, B are contants. Then the range of Af(x) is

A

`[-1,1]`

B

`[-sqrt2,sqrt2]`

C

`[0,1]`

D

`[-1,0]`

Text Solution

Verified by Experts

The correct Answer is:
A
`(1)/(sqrt2)int(d(Sinx+cosx))/((sinx+cosx)+1)=(1)/(sqrt2)tan^(-1)(sinx+cosx)+B`
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