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A sum of money at compound interest (com...

A sum of money at compound interest (compound annually) doubles itself in 4 years. In how many years will it amount to eight times of itself?

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To solve the problem step by step, we will use the concept of compound interest. ### Step 1: Understand the Problem We are given that a sum of money doubles itself in 4 years at compound interest. We need to find out how many years it will take for the same sum to amount to eight times itself. ### Step 2: Set Up the Formula The formula for the amount \( A \) in compound interest is: \[ A = P \left(1 + \frac{R}{100}\right)^N \] where: - \( P \) = Principal amount (initial sum of money) - \( R \) = Rate of interest per annum - \( N \) = Number of years ### Step 3: Case 1 - Doubling in 4 Years Since the money doubles in 4 years, we can set up the equation: \[ 2P = P \left(1 + \frac{R}{100}\right)^4 \] Dividing both sides by \( P \): \[ 2 = \left(1 + \frac{R}{100}\right)^4 \] ### Step 4: Solve for \( 1 + \frac{R}{100} \) To isolate \( 1 + \frac{R}{100} \), we take the fourth root of both sides: \[ 1 + \frac{R}{100} = 2^{1/4} \] ### Step 5: Case 2 - Finding When Amount is Eight Times Now we need to find out how many years \( N \) it will take for the amount to be eight times the principal: \[ 8P = P \left(1 + \frac{R}{100}\right)^N \] Dividing both sides by \( P \): \[ 8 = \left(1 + \frac{R}{100}\right)^N \] ### Step 6: Express 8 in Terms of 2 We know that \( 8 = 2^3 \). Therefore, we can rewrite the equation: \[ 2^3 = \left(1 + \frac{R}{100}\right)^N \] ### Step 7: Substitute \( 1 + \frac{R}{100} \) From Step 4, we know that \( 1 + \frac{R}{100} = 2^{1/4} \). Substitute this into the equation: \[ 2^3 = \left(2^{1/4}\right)^N \] ### Step 8: Simplify the Equation Using the power of a power property: \[ 2^3 = 2^{N/4} \] Since the bases are the same, we can set the exponents equal to each other: \[ 3 = \frac{N}{4} \] ### Step 9: Solve for \( N \) To find \( N \), multiply both sides by 4: \[ N = 3 \times 4 = 12 \] ### Conclusion It will take **12 years** for the sum of money to amount to eight times itself. ---
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