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Two partners A and B together lend ₹ 841...

Two partners A and B together lend ₹ 84100 at 5% compounded annually. The amount which A gets at the end of 3 years is the same as what B gets at the end of 5 years. Determine the ratio of shares of A and B.

A

`21:20`

B

`441: 400`

C

`1:4`

D

`5:21`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the ratio of the shares of partners A and B based on the compound interest they receive after different time periods. Here’s a step-by-step solution: ### Step 1: Define the variables Let: - A's investment = ₹ X - B's investment = ₹ Y - Total investment = ₹ 84100 Thus, we have: \[ X + Y = 84100 \] ### Step 2: Write the formula for compound interest The formula for the amount (A) after compound interest is given by: \[ A = P \left(1 + \frac{r}{100}\right)^n \] where: - \( P \) = principal amount (initial investment) - \( r \) = rate of interest - \( n \) = number of years ### Step 3: Calculate the amount for A and B For partner A, the amount after 3 years at 5% interest: \[ A_A = X \left(1 + \frac{5}{100}\right)^3 = X \left(1.05\right)^3 \] For partner B, the amount after 5 years at 5% interest: \[ A_B = Y \left(1 + \frac{5}{100}\right)^5 = Y \left(1.05\right)^5 \] ### Step 4: Set the amounts equal According to the problem, the amounts received by A and B are equal: \[ X \left(1.05\right)^3 = Y \left(1.05\right)^5 \] ### Step 5: Simplify the equation Dividing both sides by \( \left(1.05\right)^3 \): \[ X = Y \left(1.05\right)^{5-3} \] \[ X = Y \left(1.05\right)^2 \] ### Step 6: Express X in terms of Y Now we can express X in terms of Y: \[ X = Y \left(1.05\right)^2 \] \[ X = Y \cdot 1.1025 \] ### Step 7: Substitute into the total investment equation Substituting \( X \) in the total investment equation: \[ Y \cdot 1.1025 + Y = 84100 \] \[ Y(1.1025 + 1) = 84100 \] \[ Y(2.1025) = 84100 \] ### Step 8: Solve for Y Now, solve for Y: \[ Y = \frac{84100}{2.1025} \] \[ Y \approx 40000 \] ### Step 9: Find X Now substitute back to find X: \[ X = Y \cdot 1.1025 \] \[ X = 40000 \cdot 1.1025 \] \[ X \approx 44100 \] ### Step 10: Find the ratio of X to Y Finally, the ratio of shares of A and B is: \[ \frac{X}{Y} = \frac{44100}{40000} = \frac{441}{400} \] ### Conclusion Thus, the ratio of shares of A and B is: \[ \text{Ratio of A to B} = 441:400 \]
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S CHAND IIT JEE FOUNDATION-COMPOUND INTEREST -Question Bank - 19 (a)
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  6. A man deposited ₹ 6000 in a bank at 5% simple interest. Another man de...

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  7. The difference between compound interest and simple interest on a s...

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  8. The compound interest on a sum of money for 2 years is Rs 832 and t...

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  9. A money-lender borrows money at 4% per annum and pays the interest ...

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  13. A sum of money invested at compound interest amounts in 3 years to ₹ 2...

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  14. The compound interest on ₹ 2000 in 2 years if the rate of interest is ...

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  15. Two partners A and B together lend ₹ 84100 at 5% compounded annually. ...

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  16. A principal sum of money is lent out at compound interest compounded a...

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  18. The compound interest on a certain sum for 2 years at 10% per annum...

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  19. Two friends A and B jointly lent out ₹ 81600 at 4% compound interest. ...

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  20. Find the compound interest on Rs 24000 at 15% per annum for years...

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