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A principal sum of money is lent out at ...

A principal sum of money is lent out at compound interest compounded annually at the rate of 20% per annum for 2 years. It would give ₹ 2410 more if the interest is compounded half yearly. Find the principal sum.

A

₹ `120000`

B

₹ `125000`

C

₹ `100000`

D

₹ `110000`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will calculate the principal sum of money (P) based on the given conditions regarding compound interest. ### Step 1: Understanding the Problem We need to find the principal sum (P) that, when compounded annually at a rate of 20% for 2 years, results in an amount that is ₹2410 less than the amount when compounded half-yearly at the same rate for the same time period. ### Step 2: Calculate Amount when Compounded Annually The formula for the amount (A) when compounded annually is: \[ A = P \left(1 + \frac{R}{100}\right)^N \] Where: - \( R = 20\% \) - \( N = 2 \) years Substituting the values: \[ A_1 = P \left(1 + \frac{20}{100}\right)^2 \] \[ A_1 = P \left(1 + 0.2\right)^2 \] \[ A_1 = P \left(1.2\right)^2 \] \[ A_1 = P \times 1.44 \] ### Step 3: Calculate Amount when Compounded Half-Yearly When compounded half-yearly, the rate is halved and the number of compounding periods is doubled. Thus: - Rate for half-year = \( \frac{20}{2} = 10\% \) - Number of compounding periods = \( 2 \times 2 = 4 \) Using the formula for compound interest: \[ A_2 = P \left(1 + \frac{R/2}{100}\right)^{2N} \] Substituting the values: \[ A_2 = P \left(1 + \frac{10}{100}\right)^4 \] \[ A_2 = P \left(1 + 0.1\right)^4 \] \[ A_2 = P \left(1.1\right)^4 \] Calculating \( (1.1)^4 \): \[ (1.1)^4 = 1.4641 \] Thus: \[ A_2 = P \times 1.4641 \] ### Step 4: Set Up the Equation According to the problem, the difference between the two amounts is ₹2410: \[ A_2 = A_1 + 2410 \] Substituting the expressions for \( A_1 \) and \( A_2 \): \[ P \times 1.4641 = P \times 1.44 + 2410 \] ### Step 5: Simplify the Equation Rearranging the equation: \[ P \times 1.4641 - P \times 1.44 = 2410 \] Factoring out \( P \): \[ P (1.4641 - 1.44) = 2410 \] Calculating \( 1.4641 - 1.44 = 0.0241 \): \[ P \times 0.0241 = 2410 \] ### Step 6: Solve for P Now, divide both sides by 0.0241: \[ P = \frac{2410}{0.0241} \] Calculating the right side: \[ P = 100,000 \] ### Final Answer The principal sum is ₹100,000. ---
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S CHAND IIT JEE FOUNDATION-COMPOUND INTEREST -Question Bank - 19 (a)
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