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A man rows upstream 13 km and downstream...

A man rows upstream 13 km and downstream 28 km talking 5 hrs each time. What is the velocity in (km/hr) of the current?

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To solve the problem step by step, we can follow these instructions: ### Step 1: Define Variables Let: - \( x \) = speed of the boat in still water (in km/hr) - \( y \) = speed of the current (in km/hr) ### Step 2: Determine Upstream and Downstream Speeds - The speed of the boat when rowing upstream (against the current) is \( x - y \). - The speed of the boat when rowing downstream (with the current) is \( x + y \). ### Step 3: Use the Distance, Speed, and Time Relationship We know that: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \] From the problem, we have: - Upstream distance = 13 km, time = 5 hours - Downstream distance = 28 km, time = 5 hours ### Step 4: Set Up the Equations Using the formula for speed, we can set up the following equations: 1. For upstream: \[ x - y = \frac{13 \text{ km}}{5 \text{ hr}} \quad \text{(1)} \] 2. For downstream: \[ x + y = \frac{28 \text{ km}}{5 \text{ hr}} \quad \text{(2)} \] ### Step 5: Simplify the Equations Calculating the right side of the equations: 1. From equation (1): \[ x - y = 2.6 \quad \text{(since } \frac{13}{5} = 2.6\text{)} \] 2. From equation (2): \[ x + y = 5.6 \quad \text{(since } \frac{28}{5} = 5.6\text{)} \] ### Step 6: Solve the System of Equations Now we have the system of equations: 1. \( x - y = 2.6 \) (Equation 1) 2. \( x + y = 5.6 \) (Equation 2) To eliminate \( y \), we can add both equations: \[ (x - y) + (x + y) = 2.6 + 5.6 \] This simplifies to: \[ 2x = 8.2 \] Thus: \[ x = \frac{8.2}{2} = 4.1 \text{ km/hr} \] Now, substitute \( x \) back into one of the original equations to find \( y \): Using Equation 1: \[ 4.1 - y = 2.6 \] So, \[ y = 4.1 - 2.6 = 1.5 \text{ km/hr} \] ### Final Answer The speed of the current \( y \) is **1.5 km/hr**. ---
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S CHAND IIT JEE FOUNDATION-DISTANCE, TIME AND SPEED -Unit Test-3
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