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3.15 g of dibasic acid is present in 500...

3.15 g of dibasic acid is present in 500 mL of its 0.1 N solution. Calculate the molecular mass of the acid.

Text Solution

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3.15 g acid is present in 500 mL solution.
1000 mL contains `3.15xx2=6.3` g
`E=W/(N)=6.3/(0.1)=63`
Molecular mass of the acid
`="equivalent mass"xx"valency"`
`=63xx2=126`
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