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0.5925 g of potassium permanganate is di...

0.5925 g of potassium permanganate is dissolved in 250 `cm^(3)` of its solution. Calculate the molarity of the solution.

Text Solution

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0.5925 g of potassium permanganate is present in 250 `cm^(3)` of the solution.
1000 `cm^(3)` of the solution contain
`0.5925xx1000/(250)=2.37` g of potassium permanganate
Therefore, `"molarity"=("mass"//dm^(3))/("molecular mass")`
`=2.37/(158)=0.015`
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