Home
Class 12
MATHS
Find the number of solution of the equat...

Find the number of solution of the equation
`tan (Sigma_(r=1)^(5) cot^(-1) (2r^(2))) = (5x+6)/(6x+5)`.

Text Solution

Verified by Experts

The correct Answer is:
0
Promotional Banner

Topper's Solved these Questions

  • INVERSE TRIGONOMETRIC FUNCTIONS

    ARIHANT MATHS|Exercise Exercise (Matching Type Questions)|6 Videos
  • INVERSE TRIGONOMETRIC FUNCTIONS

    ARIHANT MATHS|Exercise Exercise 6|1 Videos
  • INVERSE TRIGONOMETRIC FUNCTIONS

    ARIHANT MATHS|Exercise Exercise (Statement I And Ii Type Questions)|14 Videos
  • INDEFINITE INTEGRAL

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|8 Videos
  • LIMITS

    ARIHANT MATHS|Exercise Exercise For Session 6|5 Videos

Similar Questions

Explore conceptually related problems

The number of solutions of the equation |x-1|-|2x-5|=2x

The number of real solution of the equation x^(2)=1-|x-5| is:

Find the number of solution of the equations |cot x|= cot x +(1)/(sin x), when in [0,2pi]

The number of solutions of the equation sqrt(x^(2))-sqrt((x-1)^(2))+sqrt((x-2)^(2))=sqrt(5) is

Find the number of solutions of the system of equations. 3x + 2y = 5, 6x + 4y = 3

Find the number of solution of the equation 1+e^(cot^2x ) =sqrt(2|sinx|-1)+(1-cos2x)/(1+sin^4x)forx in (0,5pi)dot

Find the solution of the equation: tan^-1x - cot^-1 x = tan^-1(1/sqrt3)

Find the number of real solution of the equation (cos x)^(5)+(sin x)^(3)=1 in the interval [0, 2pi]

The value of 5 * cot ( Sigma_(k =1)^(5) cot ^(-1) ( k^(2) + k + 1)) is equal to

Solve (tan^(-1) x)^(2) + (cot^(-1) x)^(2) = (5pi^(2))/(8)