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The total number of arrangements of the ...

The total number of arrangements of the letters in the expression `x^3 z^2 y^4` when written at full lengths is

A

2520

B

1260

C

610

D

none of these

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AI Generated Solution

The correct Answer is:
To find the total number of arrangements of the letters in the expression \( x^3 z^2 y^4 \) when written at full lengths, we can follow these steps: ### Step 1: Write the expression in full length The expression \( x^3 z^2 y^4 \) means we have: - 3 letters 'x' - 2 letters 'z' - 4 letters 'y' When written out fully, it looks like this: \[ xxxzzyyyy \] ### Step 2: Count the total number of letters Now, we count the total number of letters: - Total letters = 3 (from x) + 2 (from z) + 4 (from y) = 9 letters. ### Step 3: Use the formula for arrangements of letters The formula to find the number of arrangements of letters when some letters are repeated is given by: \[ \text{Total arrangements} = \frac{n!}{n_1! \times n_2! \times n_3!} \] where: - \( n \) is the total number of letters, - \( n_1, n_2, n_3 \) are the frequencies of the repeated letters. In our case: - \( n = 9 \) (total letters), - \( n_1 = 3 \) (for x), - \( n_2 = 2 \) (for z), - \( n_3 = 4 \) (for y). ### Step 4: Substitute values into the formula Substituting the values into the formula, we get: \[ \text{Total arrangements} = \frac{9!}{3! \times 2! \times 4!} \] ### Step 5: Calculate the factorials Now, we calculate the factorials: - \( 9! = 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 362880 \) - \( 3! = 3 \times 2 \times 1 = 6 \) - \( 2! = 2 \times 1 = 2 \) - \( 4! = 4 \times 3 \times 2 \times 1 = 24 \) ### Step 6: Substitute the factorials back into the equation Now substituting these values back: \[ \text{Total arrangements} = \frac{362880}{6 \times 2 \times 24} \] ### Step 7: Calculate the denominator Calculating the denominator: \[ 6 \times 2 = 12 \] \[ 12 \times 24 = 288 \] ### Step 8: Final calculation Now we can calculate the total arrangements: \[ \text{Total arrangements} = \frac{362880}{288} = 1260 \] Thus, the total number of arrangements of the letters in the expression \( x^3 z^2 y^4 \) when written at full lengths is **1260**.
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