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PQRS is a quadrilateral having 3 4 5 6 p...

PQRS is a quadrilateral having 3 4 5 6 points on PQ , QR, RS and SP respectively. The number of triangles with vertices on different sides is

A

220

B

270

C

282

D

none of these

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The correct Answer is:
To find the number of triangles that can be formed with vertices on different sides of the quadrilateral PQRS, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Points on Each Side:** - Let’s denote the number of points on each side of the quadrilateral: - Points on side PQ = 3 - Points on side QR = 4 - Points on side RS = 5 - Points on side SP = 6 2. **Determine the Combinations of Sides:** - To form a triangle, we need to select 3 sides from the 4 available sides (PQ, QR, RS, SP). The combinations of sides can be calculated using the combination formula \( C(n, r) \), where \( n \) is the total number of sides and \( r \) is the number of sides to choose. - The number of ways to choose 3 sides from 4 is: \[ C(4, 3) = 4 \] 3. **Calculate the Number of Triangles for Each Combination of Sides:** - We will calculate the number of triangles for each combination of sides by taking one point from each selected side. - **Combination 1: PQ, QR, RS** - Points = \( 3 \) (from PQ) × \( 4 \) (from QR) × \( 5 \) (from RS) - Total triangles = \( 3 \times 4 \times 5 = 60 \) - **Combination 2: QR, RS, SP** - Points = \( 4 \) (from QR) × \( 5 \) (from RS) × \( 6 \) (from SP) - Total triangles = \( 4 \times 5 \times 6 = 120 \) - **Combination 3: RS, SP, PQ** - Points = \( 5 \) (from RS) × \( 6 \) (from SP) × \( 3 \) (from PQ) - Total triangles = \( 5 \times 6 \times 3 = 90 \) - **Combination 4: SP, PQ, QR** - Points = \( 6 \) (from SP) × \( 3 \) (from PQ) × \( 4 \) (from QR) - Total triangles = \( 6 \times 3 \times 4 = 72 \) 4. **Sum the Total Number of Triangles:** - Now, we will add the number of triangles from all combinations: \[ \text{Total triangles} = 60 + 120 + 90 + 72 = 342 \] 5. **Conclusion:** - The total number of triangles that can be formed with vertices on different sides of the quadrilateral PQRS is **342**.
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