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The number of triangles that are formed ...

The number of triangles that are formed by choosing the vertices from a set of 12 points, seven of which lie on the same straight line is

A

105

B

150

C

175

D

185

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The correct Answer is:
To solve the problem of finding the number of triangles that can be formed by choosing vertices from a set of 12 points, where 7 of those points are collinear, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We have a total of 12 points, out of which 7 points are collinear (lie on the same straight line). We need to find the number of triangles that can be formed using these points. 2. **Calculate Total Combinations of Points**: To form a triangle, we need to select 3 points. If all points were non-collinear, the number of ways to choose 3 points from 12 is given by the combination formula: \[ \text{Total triangles} = \binom{12}{3} \] Using the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] We calculate: \[ \binom{12}{3} = \frac{12!}{3!(12-3)!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 \] 3. **Calculate the Combinations of Collinear Points**: Since 7 points are collinear, any triangle formed using these 7 points will not be valid (as they lie on a straight line). The number of ways to choose 3 points from these 7 collinear points is: \[ \text{Collinear triangles} = \binom{7}{3} \] Calculating this gives: \[ \binom{7}{3} = \frac{7!}{3!(7-3)!} = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = 35 \] 4. **Subtract Collinear Combinations from Total Combinations**: To find the valid triangles, we subtract the number of invalid triangles (formed by collinear points) from the total triangles: \[ \text{Valid triangles} = \text{Total triangles} - \text{Collinear triangles} \] Substituting the values we calculated: \[ \text{Valid triangles} = 220 - 35 = 185 \] 5. **Conclusion**: The number of triangles that can be formed by choosing vertices from the set of 12 points, where 7 points are collinear, is **185**.
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ML KHANNA-PERMUTATIONS AND COMBINATIONS -SET-4 MCQ
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