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The number of ways in which a team of el...

The number of ways in which a team of eleven players can be selected from from 22 players so that 2 particular players are always included and 4 naughty boys are excluded is

A

`"^16 C_9`

B

`"^16 C_11`

C

`"^20 C_9`

D

`"^20 C_5`

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AI Generated Solution

The correct Answer is:
To solve the problem of selecting a team of 11 players from 22 players, where 2 specific players must be included and 4 specific players must be excluded, we can follow these steps: ### Step 1: Determine the total number of players available for selection Initially, we have 22 players. However, since 2 players must always be included and 4 players must be excluded, we need to adjust the total number of players available for selection. - Players included: 2 (let's call them A and B) - Players excluded: 4 (let's call them C, D, E, and F) Thus, the number of players available for selection is: \[ 22 - 4 = 18 \text{ (after excluding C, D, E, and F)} \] ### Step 2: Calculate the number of players we still need to select Since we have already included 2 players (A and B), we need to select: \[ 11 - 2 = 9 \text{ players} \] ### Step 3: Determine the number of players left to choose from After excluding the 4 naughty boys, we have: \[ 18 - 2 = 16 \text{ players left (excluding A and B)} \] ### Step 4: Calculate the number of ways to choose the remaining players Now, we need to choose 9 players from the remaining 16 players. The number of ways to choose \( r \) players from \( n \) players is given by the combination formula: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] In this case, we need to calculate: \[ \binom{16}{9} \] ### Step 5: Calculate \( \binom{16}{9} \) Using the combination formula: \[ \binom{16}{9} = \frac{16!}{9!(16-9)!} = \frac{16!}{9! \cdot 7!} \] ### Step 6: Simplify the calculation We can simplify \( \binom{16}{9} \) as follows: \[ \binom{16}{9} = \frac{16 \times 15 \times 14 \times 13 \times 12 \times 11 \times 10}{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1} \] Calculating this gives: \[ \binom{16}{9} = 11440 \] ### Final Answer Thus, the number of ways in which a team of 11 players can be selected from 22 players, ensuring that 2 particular players are included and 4 naughty boys are excluded, is: \[ \boxed{11440} \] ---
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