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Locus of the point from which the differ...

Locus of the point from which the difference of the squares of lengths of tangents drawn to two given circles is constant is

A

circle

B

parabola

C

straight line

D

none

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The correct Answer is:
To find the locus of the point from which the difference of the squares of the lengths of tangents drawn to two given circles is constant, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We need to find the locus of points from which the difference of the squares of the lengths of tangents drawn to two circles is constant. Let the two circles be represented by their equations. 2. **Equations of the Circles**: Let the equations of the two circles be: - Circle 1: \( x^2 + y^2 + 2G_1x + 2F_1y + C_1 = 0 \) - Circle 2: \( x^2 + y^2 + 2G_2x + 2F_2y + C_2 = 0 \) 3. **Length of Tangents**: The length of the tangent from a point \( (A, B) \) to a circle can be given by the formula: - For Circle 1: \[ L_1 = \sqrt{A^2 + B^2 + 2G_1A + 2F_1B + C_1} \] - For Circle 2: \[ L_2 = \sqrt{A^2 + B^2 + 2G_2A + 2F_2B + C_2} \] 4. **Setting Up the Equation**: According to the problem, the difference of the squares of the lengths of the tangents is constant: \[ L_1^2 - L_2^2 = K \] where \( K \) is a constant. 5. **Substituting the Lengths**: Substitute \( L_1^2 \) and \( L_2^2 \): \[ (A^2 + B^2 + 2G_1A + 2F_1B + C_1) - (A^2 + B^2 + 2G_2A + 2F_2B + C_2) = K \] 6. **Simplifying the Equation**: Simplifying the above equation gives: \[ (2G_1 - 2G_2)A + (2F_1 - 2F_2)B + (C_1 - C_2 - K) = 0 \] 7. **Rearranging the Terms**: Rearranging the terms, we can express the equation in the form: \[ (G_1 - G_2)A + (F_1 - F_2)B = \frac{K + C_2 - C_1}{2} \] 8. **Identifying the Locus**: The equation derived is a linear equation in \( A \) and \( B \), which represents a straight line. Thus, the locus of the point from which the difference of the squares of the lengths of tangents drawn to the two circles is constant is a straight line. ### Final Answer: The locus of the point from which the difference of the squares of lengths of tangents drawn to two given circles is constant is a **straight line**.
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ML KHANNA-THE CIRCLE -Problem Set (6) (MULTIPLE CHOICE QUESTIONS)
  1. The co-ordinates of the point from which the lengths of tangents to th...

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  2. The co-ordinates of the point from which the length of tangents to the...

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  3. The radical centre of three circles described on the three sides of a ...

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  4. The radical centre of the circle x^(2)+y^(2)=1, x^(2)+y^(2)-2x=1 and x...

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  5. Length of tangent from the radical centre of the three circles x^(2)+y...

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  6. Locus of the point from which the difference of the squares of lengths...

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  7. The length of tangent from (5,1) to the circle x^(2)+y^(2)+6x-4y-3=0 ...

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  8. x^(2)+y^(2)+2lambdax +5=0 and x^(2)+y^(2)+2lambday+5=0 are the equatio...

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  9. If the tangent at the point p on the circle x^(2)+y^(2)+6x+6y=2 meets ...

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  10. The lengths of the tangents from any point on the circle 15x^(2)+15y^...

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  11. The length of the tangent drawn from any point on the circle S=x^(2)+...

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  12. A and B are two points (0,0) and (3a,0) respectively. Points P and Q a...

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  13. If the distances from the origin of the centres of the three circles x...

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  14. A pair of tangents are drawn from a point P to the circle x^(2)+y^(2)=...

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  15. A point P moves so that length of tangent from P to the circle x^(2)+y...

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  16. x^(2)+y^(2)-4x-2y-11=0 is a circle to which tangents are drawn from t...

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  17. Equation of the circle coaxial with the circles 2x^(2)+2y^(2)-2x+6y-3=...

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  18. ABCD is a square of side length 2. C(1) is a circle inscribed in the s...

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  19. ABCD is a square of side length 2. C(1) is a circle inscribed in the s...

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  20. ABCD is a square of side length 2. C(1) is a circle inscribed in the s...

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