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A square has one vertex at the vertex of...

A square has one vertex at the vertex of the parabola `y^2=4a x` and the diagonal through the vertex lies along the axis of the parabola. If the ends of the other diagonal lie on the parabola, the coordinates of the vertices of the square are `(4a ,4a)` (b) `(4a ,-4a)` `(0,0)` (d) `(8a ,0)`

A

`(4a,4a)`

B

`(4a-4a)`

C

`(0,0)`

D

`(8a,0)`

Text Solution

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The correct Answer is:
A, B, C, D
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