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intsqrtx e^(sqrtx)dx is equal to...

`intsqrtx e^(sqrtx)dx` is equal to

A

`2sqrtx-e^(sqrtx)-4sqrt(xe)^(sqrtx)`

B

`(2x -4 sqrtx+4)e^(sqrtx)`

C

`(1-4sqrtx)e^(sqrtx)`

D

None

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • int sqrtx e^(sqrtx) dx is equal to

    A
    `2sqrtx-e^sqrtx +4sqrt(xe^sqrtx)+C`
    B
    `(2x-4sqrtx+4)e^sqrtx+C`
    C
    `(2x+4sqrtx+4)e^sqrt4 +C`
    D
    `(1+4sqrtx)e^sqrtx+C`

  • What is int sqrtx e^(sqrtx) dx equal to ? Where 'c' is a constant of integration

    A
    `2 e^(sqrtx) (x -2 sqrtx + 2) + c`
    B
    `2e^(sqrtx) (x +2 sqrtx + 2) + c`
    C
    `2e^(sqrtx) (x + 2 sqrtx -2) + c`
    D
    `2 e^(sqrtx) (x -2 sqrt -2) + c`

  • The value of int(e^(sqrtx))/(sqrtx(1+e^(2sqrtx)))dx is equal to (where, C is the constant of integration)

    A
    `tan^(-1)(2e^(sqrtx))+C`
    B
    `ln((1+e^(x))/(1-e^(sqrtx)))+C`
    C
    `2tan^(-1)(e^(sqrtx))+C`
    D
    `(tan^(-1)x)e^(sqrtx)+C`

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