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int(4e^x+6e^(-x))/(9e^x-4e^(-x))dx=A x+B...

`int(4e^x+6e^(-x))/(9e^x-4e^(-x))dx=A x+Blog(9e^(2x)-4)+C ,t h e n` A=_________ _, B=_________, C=___________

Text Solution

Verified by Experts

The correct Answer is:
`A=-3/2,B =35/36` C = any real constant
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