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Let I =int(e^(x))/(e^(4x)+e^(2x)+1)dx ,...

Let I `=int(e^(x))/(e^(4x)+e^(2x)+1)dx` , J = `int(e^(-x))/(e^(-4x)+e^(-2x)+1)dx`. Then for an arbitary constant C, the value of I - J equals

A

`1/2log((e^(4x)-e^(2x)+1)/(e^(4x+e^(2x))+1))+C`

B

`1/2log((e^(2x)+e^(x)+1)/(e^(2x)-e^(x)+1))+C`

C

`1/2log((e^(2x)-e^(x)+1)/(e^(2x)+e^(x)+1))+C`

D

`1/2log((e^(4x)+e^(2x)+1)/(e^(4x)-e^(2x)+1))`

Text Solution

Verified by Experts

The correct Answer is:
C
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