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If Im = int1^(e) (log x)^(m) dx, then I...

If `I_m = int_1^(e) (log x)^(m) dx, ` then `I_m+I_(m-1)` =

A

me

B

2e

C

3e

D

e

Text Solution

Verified by Experts

The correct Answer is:
D
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