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CH3 -CH =CH2 +HI to X where X is...

`CH_3 -CH =CH_2 +HI to X ` where X is

A

`CH_3 -CH_2-CH_2 -I`

B

`CH_3- underset(I ) underset(|)(CH) -CH_3`

C

`CH_3 -CH_2 -CH_3`

D

`CH_3 - CH_3 +CH_4`

Text Solution

Verified by Experts

The correct Answer is:
B
`CH_3 -CH= CH_2 +HI to CH_3 -underset(I) underset(|)CH-CH_3`
Here addition of HI is according to markonikov.s rule.
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