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Using the following cell reaction find E...

Using the following cell reaction find `E_(cell)`
(i) `Cu(s) to Cu^(2+)(0.5M) + 2e^-` `E^@`= -0.34V
(ii) `Ag^+(0.45M) + e^- to Ag` `E^@` = 0.80V

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E^@ values for the half cell reactions are given below : Cu^(2+) + e^(-) to Cu^(+) , E^@ =0.15 V Cu^(2+) + 2e^(-) to Cu, E^@ =0.34 V What will be the E^@ of the half-cell : Cu^(+) + e^(-) to Cu ?

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