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At 293 K, ethyl acetate has vapour pres...

At 293 K, ethyl acetate has vapour pressure of 72.8 torr ethyl proprionatr has vapour pressure of 27 . 7 torr. Assuming their mixture to obey Raoult's law determine the vapour pressure of the mixture containing 25 g ethyl acetate and 50 g of ethyl propomoate

Text Solution

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Mass of ethyl acetate `, W_(EA) = 25 g`
Molar mass of ethyl acetate `(CH_(3) CO O C_(2) H_(5))`
`M_(EA) = 48 + 32 + 8 = 88 g mol^(-1)`
Mass of ethyl propionate, `W_(EP) = 50 g`
Molar mass of ethyl propomoate ` CH_(3) CH_(2) CO OC_(2) H_(5)`
`M_(EP) = (88 + 14) g mol^(-1)`
`= 102 g mol^(-1)`
`:. n_(EA) = (W_(EA))/( M_(EA)) = (25)/(88) ` mol
= 0 . 284 mol
`n_(EP) = (W_(EP))/( M_(EP)) = (50)/(102) ` mol
=0 . 490 mol
`x_(EA) = (n_(EA))/( n_(EA) + n_(EP)) = ( 0 . 284)/(0 . 284 = 0 .490) = (0.284)/( 0 . 77)`
= 0 . 37
`x_(EP) = 1 - x_(EA)`
`= 1 - 0 . 37 = 0 . 63 `
` P_(EA)^(@) = 72 . 8 "torr " , P_(EP)^(@)`
`= 27 . 7 ` torr
`P_("Solution") = P_(EA)^(@) xx x_(EA) + P_(EA)^(@) xx x_(EP)`
`= ( 72 . 8 xx 0 . 37 + 27 . 7 xx 0 . 63) ` torr
= 276 . 94 + 17 . 45
= 44 . 49 torr
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