70 g of glucose and 40 g of NaCl are dissolved in 900 g of water, calculate the mole fraction of each component?

Explanation

`n_("water") = (12 g)/( 18 g mol^(-1)) = 0 . 67` mol
`n_(ethanol ") = ( 92 g)/( 46 g mol^(-1)) = 2 mol`
`x_("water ") = (n_("water"))/( n _("water ") + n_("ethanol"))`
`= ( 0 . 67 )/( 0 . 67 + 2 . 00) = ( 0 . 67)/( 2 . 67) = 0 . 251 ` 1