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Find the molarity and molality of a 37% ...

Find the molarity and molality of a `37%` solution of HCI by weight . The density of the solution is 1 19 g/cc. and the molec lar mass of hydrochloric acid is 36. 5

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The correct Answer is:
16.09 m, 12.06 M

Let mass of `37%` HCI solution = 100 g
`:.` Mass of HCI , `W_(B) = 37 g`
Mas of solvet, `W_(A) = 100 - 37`
`= 63 g = 0.063 kg `
Moles of HCI =`(37 G)/( 36.5 g mol^(-1))` = 1.014 mol
(Molar mass of HCI = 36 . 5g ` mol^(-1)` )
Molality `= ("Moles of HCI")/("Mass of solvent (kg)") = (1.014)/(0.063) ` mol `kg^(-1)`
`= 16.09 m `
Volume of solution
`= ("Mass of solution ")/( "Density of solution ") = (100 g)/( 1 . 19 g cm^(-3))`
`= 84 . 0 3 mL = 0.084 L`
Molarity `= ("Moles of solute")/("Volume of solution (L)")`
`= (1 . 014 mol)/( 0.084 L) = (1014)/(84) = mol L^(-1)`
= 12.07 M
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