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200 cm^3 of an aqueous solution of a pro...

200 `cm^3` of an aqueous solution of a protein contains 1.26g of the protein . The osmotic pressure of such a solution at 300K is found to be `2.7 xx 10^-3` bar. Calculate the molar mass of the protein (R=0.083 L bar `mol^-1 K^-1`)

Text Solution

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The correct Answer is:
60, 303, 5u
`V = 200 cm^(3) = 0.2 L`
`W_(B) = 1.26 g, M_(B) = ?`
`= 2.57 xx 10^(-3) atm, T = 300 K`
`R = 0.0821 L atm K^(-1) mol^(-1)`
`pi = (W_(B))/(M_(B)) (R_(T))/(V)`
`M_(B) = (W_(B) xx R xx T)/(pi xx V)`
`=((1.26 g) xx (0.082) L atm K^(-1) mol^(-1) xx (300 K))/((2.57 xx 10^(-3) atm)xx (0.2))`
`= 60 .37704 xx 10^(3) g mol = 60337 .04 u`
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