Comprehension 2 Consider the system of linear equations `alphax+y+z=m x+alphay+z=n x+y+alphaz=p` If `alpha=1\ &\ m!=p` then the system of linear equations has- a. no solution b. `\ ` infinite solutions c. unique solution d. `\ ` unique solution `if\ p=n`

Comprehension 2 Consider the system of linear equations alphax+y+z=m x+alphay+z=n x+y+alphaz=p If alpha=-2\ 7\ m+n+p!=0 then system of linear equations has- a. no solution b. infinite solutions c. unique solution d. finitely many solution

Consider the system of equations alphax+y+z = p, x+alphay+z=q and x+y+alphaz=r , then the sum of all possible distinct value(s) of alpha for which system does not possess a unique solution is

For what value(s) of alpha will the system of linear equations alphax + 3y = alpha - 3 and 12x + alpha y = alpha has a unique solution?

The system of equations alphax+y+z=alpha-1, x+alphay+z=alpha-1 x+y+alphaz=alpha-1 and has no solution if alpha is

The system of equations x+2y+3z=4 , 2x+3y+4z=5 , 3x+4y+5z=6 has a. infinite many solution b.no solution c. unique solution d. none of these.

A pair of linear equations which has a unique solution x = 2 and y = -3 is

The system of linear equations x + y + z = 2 2x + y -z = 3 3x + 2y + kz = 4 has a unique solution, if

The system of equations alpha(x-1)+y+z=-1, x+alpha(y-1)+z=-1 and x+y+alpha(z-1)=-1 has no solution, if alpha is equal to

Let the system of linear equations A[x y z]=[0 1 0] where A is a matrix of set X If the system of linear equation has infinite solution then number of value of alpha is infinite If the system of linear equation has infinite solution then number of matrices is infinite If the system of linear equation has infinite solution then number of value of alpha is only 4 If the system of linear equation has infinite solution then number of matrices is 4

The system of linear equations x+y+z=2,2x+y-z=3, 3x+2y+kz=4 has a unique solution if