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The standard reduction potential E^(@) o...

The standard reduction potential `E^(@)` of the following systems are:-
`{:(System,E^(@)("volts")),((i)MnO_(4)^(-)+8H^(+)+5e^(-)rarrMn^(2+)+4H_(2)O,1.51),((ii)Sn^(4+)+2e^(-)rarrSn^(2+)0.15,),((iii)Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)rarr2Cr^(3+)+7H_(2)O,1.33),((iv)Ce^(4+)+e^(-)rarrCe^(3+)1.61,):}`
The oxidising power of the various species decreases in the order

A

`Ce^(4+) gt Cr_(2)O_(7)^(2-) gt Sn^(4+) gt MnO_(4)^(-)`

B

`Ce^(4+)gt MnO_(4)^(-) gt Cr_(2)O_(7)^(2-) gt Sn^(4+)`

C

`Cr_(2)O_(7)^(2-) gt Sn^(4+) gt Ce^(4+) gt MnO_(4)^(-)`

D

`MnO_(4)^(-) gt Ce^(4+) gt Sn^(4+) gt Cr_(2)O_(7)^(2-)`

Text Solution

Verified by Experts

The correct Answer is:
B

More the reduction potential stronger the oxidising agent.
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For reaction : Cr_(2)O_(7)^(-2)+14H^(+)rarr2Cr^(+3)+7H_(2)O , How many e^(-)s are required

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MnO_(4)^(-) + 8H^(+) + 5e^(-) rightarrow Mn^(2+) + 4H_(2)O , E^(@) = 1.51V MnO_(2) + 4H^(+) + 2e^(-) righarrow Mn^(2+) + 2H_(2)O E^(@) = 1.23V E_(MnO_(4)^(-)|MnO_(2)

In the reaction: Cr_(2)O_(7)^(2-) + 14H^(o+) + 6I^(Ө) rarr2Cr^(3+) + 3H_(2)O + 3I_(2) Which element is reduced?

For the reactions {:(MnO_(4)^(-)+8H^(+)+5e^(-)rarr Mn^(2+)4H_(2)O","E^(o) = + 1.51 V),(MnO_(2)+4H^(+)+ 2e^(-) rarr Mn^(2+)+2H_(2)O"," E^(o)= + 1.23 V ):} then for the reaction : MnO_(4)^(-) + 4H^(+) + 3e^(-) rarr MnO_(2)+2H_(2)O","E^(o)

Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox titration. Some half cell reaction and their standard potentials are given below: MnO_(4)^(-)(aq) +8H^(+)(aq) +5e^(-) rarr Mn^(2+)(aq) +4H_(2)O(l) E^(@) = 1.51V Cr_(2)O_(7)^(2-)(aq) +14H^(+) (aq) +6e^(-) rarr 2Cr^(3+)(aq) +7H_(2)O(l), E^(@) = 1.38V Fe^(3+) (aq) +e^(-) rarr Fe^(2+) (aq), E^(@) = 0.77V CI_(2)(g) +2e^(-) rarr 2CI^(-)(aq), E^(@) = 1.40V Identify the only correct statement regarding quantitative estimation of aqueous Fe(NO_(3))_(2)

Standard electrode potentials of few half-cell reactions are given below : {:(MnO_4^(-)+8H^(+)+5e^(-) to Mn^(2+)+ 4H_2O,,E^@=1.51V),(Cr_2O_7^(2-)+14H^(+)+6e^(-)to 2Cr^(3+)+7H_2O,,E^@=1.33V),(Fe^(3+)+e^(-)to Fe^(2+),,E^@=0.77V),(Cl_2+2e^(-) to 2Cl^(-),,E^@=1.36):} Based on the above information match the column I with column II and mark the appropriate choice.

Complete the following chemical equations : (i) Cr_(2)O_(7)^(-) + H^(+) + I^(-) rarr (ii) MnO_(4)^(-) + NO_(2)^(-) + H^(+) rarr

The standard reduction potentials of some half cell reactions are given below: PbO_2+4H^++2e^(-)hArrPb^(2+)+2H_(2)O , E^@=1.455 V MnO_4^(-)+8H^++5e^(-)hArrMn^(2+)+4H_(2)O , E^@=1.51 V Ce^(4+)+e^(-)hArrCe^(3+), E^@=1.61 V H_2O_2+2H^++2e^(-)hArr 2H_2O, E^@=1.71 V Pick out the correct statement:

The standard electrode potential for the following reaction is +1.33 V. What is the potential at pH=2.0? Cr_(2)O_(7)^(2-)(aq,1M)+14H^(+)(aq)+6e^(-)to2Cr^(3+)(aq,1M)+7H_(2)O(l)

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