Four moles of electrons were transferred from anode to cathode in an experiment on electrolysis of water. The total volume of the tow gases (dry and at `STP)` produced will be approximately (in litres)

Options

A. `22.4`
B. `44.8`
C. `67.2`
D. `89.4`

Explanation

To solve the problem of determining the total volume of gases produced during the electrolysis of water when 4 moles of electrons are transferred, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Electrolysis of Water**:
The electrolysis of water can be represented by the following reaction:
\[ 2H_2O \rightarrow 2H_2 + O_2 \]
This reaction shows that 2 moles of water produce 2 moles of hydrogen gas and 1 mole of oxygen gas.

2. **Electrons Involved in the Reaction**:
From the balanced reaction, we can see that for every 2 moles of water that undergo electrolysis, 4 moles of electrons are transferred (2 moles of electrons per mole of water). Therefore, if 4 moles of electrons are transferred, we can deduce that:
\[ 2 \text{ moles of } H_2O \text{ produce } 2 \text{ moles of } H_2 \text{ and } 1 \text{ mole of } O_2 \]

3. **Scaling the Reaction**:
Since 4 moles of electrons are transferred, we need to scale the reaction:
\[ 2H_2O \rightarrow 2H_2 + O_2 \quad \text{(4 electrons)} \]
This means that for every 4 moles of electrons, we produce:
- 2 moles of hydrogen gas (H₂)
- 1 mole of oxygen gas (O₂)

4. **Calculating Total Moles of Gases**:
The total moles of gases produced are:
\[ 2 \text{ moles of } H_2 + 1 \text{ mole of } O_2 = 3 \text{ moles of gases} \]

5. **Volume of Gases at STP**:
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, the total volume of gases produced can be calculated as:
\[ \text{Total Volume} = \text{Total Moles} \times 22.4 \text{ L/mole} \]
Substituting the total moles:
\[ \text{Total Volume} = 3 \text{ moles} \times 22.4 \text{ L/mole} = 67.2 \text{ liters} \]

### Final Answer:
The total volume of the two gases produced will be approximately **67.2 liters**.