x,y and z in the following processes are respectively
(i) `P_(2)O_(5) +....x... rarr Ca_(3)(PO_(4))_(2)`
(ii) `2Cu_(2)O + Cu_(2)S rarr ...y... +SO_(2) uarr`
(iii) `Fe_(2)O_(3) +2CO rarr ....x ... + 3CO_(2)uarr`

Options

A. `3Ca, CuSO_(4), Fe`
B. `3Ca(OH)_(2),6Cu, FeO`
C. `3CaO, 6Cu, 2Fe`
D. `3CaO_(2), CuS, FeO`

Answer

To solve the question, we need to identify the missing substances (x, y, and z) in the given chemical reactions.

### Step-by-Step Solution:

1. **Identify x in the first reaction:**
- The reaction is:
\[ P_2O_5 + x \rightarrow Ca_3(PO_4)_2 \]
- To produce calcium phosphate \((Ca_3(PO_4)_2)\), we need calcium oxide \((CaO)\). The balanced equation shows that 3 moles of \(CaO\) are required to react with \(P_2O_5\).
- Therefore, \(x = 3 \, CaO\).

2. **Identify y in the second reaction:**
- The reaction is:
\[ 2Cu_2O + Cu_2S \rightarrow y + SO_2 \]
- Here, \(Cu_2O\) (copper(I) oxide) reacts with \(Cu_2S\) (copper(I) sulfide) to produce metallic copper and sulfur dioxide. Balancing the equation shows that 6 moles of copper are produced.
- Therefore, \(y = 6 \, Cu\).

3. **Identify z in the third reaction:**
- The reaction is:
\[ Fe_2O_3 + 2CO \rightarrow z + 3CO_2 \]
- In this reduction reaction, \(Fe_2O_3\) (ferric oxide) reacts with carbon monoxide to produce iron metal and carbon dioxide. Balancing the equation shows that 2 moles of iron are produced.
- Therefore, \(z = 2 \, Fe\).

### Final Answers:
- \(x = 3 \, CaO\)
- \(y = 6 \, Cu\)
- \(z = 2 \, Fe\)

### Summary:
The values for x, y, and z in the reactions are:
- \(x = 3 \, CaO\)
- \(y = 6 \, Cu\)
- \(z = 2 \, Fe\)