Home
Class 12
PHYSICS
Statement-1: The acceleration of a parti...

Statement-1: The acceleration of a particle near the earth surface differs slightly from the gravitational acceleration
Statement-2: The earth is not a uniform sphere and because the earth rotates.

A

Statement-1 is true, statement-2 is true: Statement-2 is a correct explanation for statement-1

B

Statement-1 is true, Statement-2 is true, Statement-2 is not a correct explanation for Statement-1

C

Statement-1 is true, Statement-2 is false.

D

Statement-1 is false, Statement-2 is true.

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will break down the reasoning step by step. ### Step 1: Understanding Statement-1 Statement-1 claims that the acceleration of a particle near the Earth's surface differs slightly from the gravitational acceleration. - **Explanation**: The standard value of gravitational acceleration (g) at the Earth's surface is approximately 9.8 m/s². However, this value can vary slightly based on geographical location due to factors such as altitude and the Earth's shape. ### Step 2: Understanding Statement-2 Statement-2 states that the Earth is not a uniform sphere and that it rotates. - **Explanation**: The Earth is an oblate spheroid, meaning it is slightly flattened at the poles and bulging at the equator due to its rotation. This shape affects the gravitational acceleration experienced at different points on the surface. ### Step 3: Analyzing the Relationship Between the Two Statements Now we need to determine if Statement-2 provides a correct explanation for Statement-1. - **Reasoning**: The non-uniform shape of the Earth (being an oblate spheroid) means that points at the equator are farther from the center of the Earth than points at the poles. This variation in distance from the center affects the gravitational force experienced at different locations, leading to slight differences in the acceleration due to gravity. Additionally, the rotation of the Earth causes a centrifugal effect that also influences the effective gravitational acceleration. ### Conclusion Based on the analysis: - Statement-1 is true because the acceleration due to gravity does vary slightly at different locations on the Earth's surface. - Statement-2 is also true as it correctly describes the Earth's shape and rotation, which explains the variations in gravitational acceleration. Thus, we conclude that Statement-2 is indeed the correct explanation for Statement-1. ### Final Answer Both statements are true, and Statement-2 is the correct explanation for Statement-1.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    ALLEN|Exercise Exercise 4 A (Conceptual Subjective Exercise)|14 Videos
  • GRAVITATION

    ALLEN|Exercise Exercise 4 B (Brain Storming Subjective Exercise)|20 Videos
  • GRAVITATION

    ALLEN|Exercise Exercise 2 (Brain Teasers)|27 Videos
  • GEOMETRICAL OPTICS

    ALLEN|Exercise subjective|14 Videos
  • KINEMATICS-2D

    ALLEN|Exercise Exercise (O-2)|46 Videos

Similar Questions

Explore conceptually related problems

The value of acceleration due to gravity at the surface of earth

The acceleration due to gravity at a depth R//2 below the surface of the earth is

Find the acceleration of a particle placed on the surface of the earth at the equator, due to the earth rotation. The radius of earth is 6400 km and time period of revolution of the earth about its axis is 24 h.

Acceleration due to gravity at earth's surface is 10 m ^(-2) The value of acceleration due to gravity at the surface of a planet of mass 1/2 th and radius 1/2 of f the earth is -

The acceleration of a body due to the attraction of the earth (radius R) at a distance 2R form the surface of the earth is (g=acceleration due to gravity at the surface of the earth)

Gravitational acceleration on the surface of a planet is (sqrt6)/(11)g. where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is (2)/(3) times that of the earth. If the escape speed on the surface of the earht is taken to be 11 kms^(-1) the escape speed on the surface of the planet in kms^(-1) will be

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of earth =12800 km and it takes 24 hour for the earth to complete one revolution about its axis.

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

Calculate the distance from the surface of the earth at which above the surface, acceleration due to gravity is the same as below the earth.