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Two absolute scales X and Y assigned num...

Two absolute scales `X` and `Y` assigned numerical values `200` and `450` to the triple of water. What is the relation between `T_(X) ` and `T_(Y)` ?

A

`9T_(X)= 4T_(Y)`

B

`4T_(X)= 9T_(Y)`

C

`T_(X) = 3T_(Y)`

D

None of these

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The correct Answer is:
To find the relation between the temperatures \( T_X \) and \( T_Y \) assigned to the triple point of water on two different absolute scales \( X \) and \( Y \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the given values**: - The triple point of water is assigned a value of 200 on scale \( X \) and 450 on scale \( Y \). - We denote the triple point of water in Kelvin as \( T_K = 273.15 \, \text{K} \). 2. **Set up the equations**: - From the problem, we can express the temperatures on the scales as: \[ T_X = 200 \, \text{(scale X)} \] \[ T_Y = 450 \, \text{(scale Y)} \] 3. **Relate the scales to Kelvin**: - Since the triple point of water is the same physical temperature, we can relate the two scales to Kelvin: \[ T_X = k_X \cdot 200 \] \[ T_Y = k_Y \cdot 450 \] - Here, \( k_X \) and \( k_Y \) are the conversion factors from scales \( X \) and \( Y \) to Kelvin. 4. **Find the conversion factors**: - We know that at the triple point of water: \[ T_X = T_K \implies k_X \cdot 200 = 273.15 \implies k_X = \frac{273.15}{200} \] \[ T_Y = T_K \implies k_Y \cdot 450 = 273.15 \implies k_Y = \frac{273.15}{450} \] 5. **Relate \( T_X \) and \( T_Y \)**: - Now we can express \( T_X \) and \( T_Y \) in terms of \( T_K \): \[ T_X = \frac{273.15}{200} \cdot 200 = 273.15 \] \[ T_Y = \frac{273.15}{450} \cdot 450 = 273.15 \] - Since both equal \( T_K \), we can set up the ratio: \[ \frac{T_X}{T_Y} = \frac{\frac{273.15}{200} \cdot 200}{\frac{273.15}{450} \cdot 450} = \frac{450}{200} \] 6. **Simplify the ratio**: - Simplifying the ratio gives: \[ \frac{T_X}{T_Y} = \frac{450}{200} = \frac{9}{4} \] - Therefore, we can express this relationship as: \[ 9 T_X = 4 T_Y \] ### Final Relation: Thus, the relation between \( T_X \) and \( T_Y \) is: \[ 9 T_X = 4 T_Y \]

To find the relation between the temperatures \( T_X \) and \( T_Y \) assigned to the triple point of water on two different absolute scales \( X \) and \( Y \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the given values**: - The triple point of water is assigned a value of 200 on scale \( X \) and 450 on scale \( Y \). - We denote the triple point of water in Kelvin as \( T_K = 273.15 \, \text{K} \). ...
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ALLEN-GEOMETRICAL OPTICS-EXERCISE -01
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