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A U-tube has a liquid of density rho(0) ...

A U-tube has a liquid of density `rho_(0)` at `0^(@) C`. In the two limbs they are kept to a length `l_(1)` and `l_(2)` at a constant temperature of `t_(1)` and `t_(2)` respectively. Then, the cubical expansion coefficient will be

A

`(l_(1)-l_(2))/(l_(2)t_(1)-l_(1)t_(2))`

B

`(l_(1)-l_(2))/(l_(1)t_(1)-l_(2)t_(2))`

C

`(l_(1)+l_(2))/(l_(2)t_(1)+l_(1)t_(2))`

D

`(l_(1)+l_(2))/(l_(1)t_(1)+l_(2)t_(2))`

Text Solution

Verified by Experts

The correct Answer is:
A

Pressure at the bottom In both arms will be equal `((rho_(0))/(1+gammat_(1)))l_(1) = ((rho_(0))/(1+gammat_(2)))l_(2) = implies gamma = (l_(1) - l_(2))/(l_(2)t_(1) - l_(1)t_(2))`
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