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When water is heated from 0^(@)C to 4^(@...

When water is heated from `0^(@)C` to `4^(@)C` and `C_(P)` and `C_(V)` are its specific heats at constant pressure and constant volume respectively , then :-

A

`C_(P)gt C_(V)`

B

`C_(P)lt C_(V)`

C

`C_(P) = C_(V)`

D

`C_(P) - C_(V) = R`

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The correct Answer is:
To solve the problem of determining the relationship between the specific heats \( C_P \) and \( C_V \) of water when it is heated from \( 0^\circ C \) to \( 4^\circ C \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Specific Heats**: - \( C_P \) is the specific heat at constant pressure. - \( C_V \) is the specific heat at constant volume. - We need to analyze the behavior of water as it is heated from \( 0^\circ C \) to \( 4^\circ C \). 2. **Applying the First Law of Thermodynamics**: - The first law of thermodynamics states: \[ \Delta Q = \Delta U + W \] - Where \( \Delta Q \) is the heat added, \( \Delta U \) is the change in internal energy, and \( W \) is the work done. 3. **Expressing Heat Added**: - The heat added when heating the water can be expressed as: \[ \Delta Q = n C_P \Delta T \] - Here, \( n \) is the number of moles and \( \Delta T \) is the change in temperature. 4. **Change in Internal Energy**: - The change in internal energy can be expressed as: \[ \Delta U = n C_V \Delta T \] 5. **Work Done**: - The work done on or by the system can be expressed as: \[ W = P \Delta V \] 6. **Combining the Equations**: - Substituting these expressions into the first law gives: \[ n C_P \Delta T = n C_V \Delta T + P \Delta V \] 7. **Analyzing the Volume Change**: - When water is heated from \( 0^\circ C \) to \( 4^\circ C \), it actually contracts before expanding. At \( 4^\circ C \), water reaches its maximum density. - This means that as water is heated, the volume decreases, leading to a negative work done (\( P \Delta V < 0 \)). 8. **Conclusion**: - Rearranging the equation gives: \[ n C_P \Delta T < n C_V \Delta T \] - This implies: \[ C_P < C_V \] ### Final Answer: Thus, the relationship between the specific heats is \( C_P < C_V \).

To solve the problem of determining the relationship between the specific heats \( C_P \) and \( C_V \) of water when it is heated from \( 0^\circ C \) to \( 4^\circ C \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Specific Heats**: - \( C_P \) is the specific heat at constant pressure. - \( C_V \) is the specific heat at constant volume. - We need to analyze the behavior of water as it is heated from \( 0^\circ C \) to \( 4^\circ C \). ...
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