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5n , n and 5n moles of a monoatomic , di...

`5`n , n and `5`n moles of a monoatomic , diatomic and non-linear polyatomic gases (which do not react chemically with each other ) are mixed at room temperature . The equivalent degree of freedom for the mixture is :-

A

`(25)/(7)`

B

`(48)/(11)`

C

`(52)/(11)`

D

`(50)/(11)`

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The correct Answer is:
To find the equivalent degree of freedom for the mixture of gases, we can follow these steps: ### Step 1: Identify the degree of freedom for each type of gas - **Monoatomic gas**: The degree of freedom (F1) is 3. - **Diatomic gas**: The degree of freedom (F2) is 5. - **Non-linear polyatomic gas**: The degree of freedom (F3) is 6. ### Step 2: Identify the number of moles for each type of gas - **Monoatomic gas**: n1 = 5n moles - **Diatomic gas**: n2 = n moles - **Non-linear polyatomic gas**: n3 = 5n moles ### Step 3: Use the formula for equivalent degree of freedom The formula for the equivalent degree of freedom (F) for the mixture is given by: \[ F = \frac{F1 \cdot n1 + F2 \cdot n2 + F3 \cdot n3}{n1 + n2 + n3} \] ### Step 4: Substitute the values into the formula Substituting the values we have: \[ F = \frac{(3 \cdot 5n) + (5 \cdot n) + (6 \cdot 5n)}{5n + n + 5n} \] ### Step 5: Simplify the equation Calculating the numerator: \[ = \frac{(15n) + (5n) + (30n)}{11n} \] Combine the terms in the numerator: \[ = \frac{50n}{11n} \] ### Step 6: Final calculation Now, simplifying further gives: \[ F = \frac{50}{11} \] ### Conclusion Thus, the equivalent degree of freedom for the mixture is: \[ \frac{50}{11} \]

To find the equivalent degree of freedom for the mixture of gases, we can follow these steps: ### Step 1: Identify the degree of freedom for each type of gas - **Monoatomic gas**: The degree of freedom (F1) is 3. - **Diatomic gas**: The degree of freedom (F2) is 5. - **Non-linear polyatomic gas**: The degree of freedom (F3) is 6. ### Step 2: Identify the number of moles for each type of gas ...
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