Pressure versus temperature graph of an ideal gas is as shown in figure. Density of the gas at point A is `rho_(0).` Density at B will be

Options

A. `(3)/(4)rho_(0)`
B. `(3)/(2)rho_(0)`
C. `(4)/(3)rho_(0)`
D. `2rho_(0)`

Answer

B

Explanation

Ideal gas equation `P = (rho)/(M)RT`
For state `A` :
`P_(0) = (rho_(0))/(M) RT_(0)`
For state `B` `3P_(0) = (rho)/(M) R2T_(0) implies rho = (3)/(2)rho_(0)`