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N molecules each of mass m of gas A and 2N molecules each of mass 2m of gas B are contained in the vessel which is maintained at a temperature T. The mean square of velocity of the molecules of B type is denoted by `v^(2)` and the mean square of the x-component of the velocity of A type is denoted by `w^(2).` The ratio of `w^(2):v^(2)` is

A

`1`

B

`2`

C

`1//3`

D

`2//3`

Text Solution

Verified by Experts

The correct Answer is:
D

`V_(A)= sqrt((3RT)/(m)) = (w)/(sqrt(3)) , V_(B) = sqrt((3RT)/(2m)) = v implies (w^(2))/(v^(2)) = (2)/(3)`
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