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The internal energy of a system remains ...

The internal energy of a system remains constant when it undergoes
(i) a cyclic process
(ii) an isothermal process
(iii) an adiabatic process
(iv) any process in which the heat given out by the system equal to the work done on the system

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The correct Answer is:
To determine when the internal energy of a system remains constant, we will analyze each of the given processes: cyclic, isothermal, adiabatic, and a specific process where the heat given out equals the work done on the system. ### Step-by-Step Solution: 1. **Cyclic Process**: - In a cyclic process, the system returns to its initial state after a series of changes. - Since the internal energy depends only on the state of the system (temperature, pressure, volume), and the initial and final states are the same, the change in internal energy (ΔU) is zero. - **Conclusion**: Internal energy remains constant. **(Correct)** 2. **Isothermal Process**: - An isothermal process occurs at a constant temperature. - Since temperature is constant, the change in temperature (ΔT) is zero. - The change in internal energy (ΔU) is related to the change in temperature. Therefore, ΔU = nC_vΔT = 0. - **Conclusion**: Internal energy remains constant. **(Correct)** 3. **Adiabatic Process**: - In an adiabatic process, there is no heat exchange with the surroundings (Q = 0). - According to the first law of thermodynamics: ΔU = Q - W. - Since Q = 0, we have ΔU = -W. This indicates that any work done will change the internal energy. - **Conclusion**: Internal energy does not remain constant. **(Incorrect)** 4. **Any Process Where Heat Given Out Equals Work Done on the System**: - If the heat given out by the system equals the work done on the system, we can express this using the first law of thermodynamics: Q = ΔU + W. - If the heat given out (Q) is negative (since it is rejected), and it equals the work done on the system (also negative), we can set Q = -W. - Substituting this into the first law gives us: -W = ΔU + W. Rearranging gives ΔU = 0. - **Conclusion**: Internal energy remains constant. **(Correct)** ### Final Answer: The internal energy of the system remains constant in the following processes: - (i) Cyclic process - (ii) Isothermal process - (iv) Any process in which the heat given out by the system equals the work done on the system Thus, the correct options are (i), (ii), and (iv). ---

To determine when the internal energy of a system remains constant, we will analyze each of the given processes: cyclic, isothermal, adiabatic, and a specific process where the heat given out equals the work done on the system. ### Step-by-Step Solution: 1. **Cyclic Process**: - In a cyclic process, the system returns to its initial state after a series of changes. - Since the internal energy depends only on the state of the system (temperature, pressure, volume), and the initial and final states are the same, the change in internal energy (ΔU) is zero. - **Conclusion**: Internal energy remains constant. **(Correct)** ...
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