One mole of an ideal gas at an initial t...

One mole of an ideal gas at an initial temperature of T K does 6 R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is `5/3` , the final temperature of gas will be :-

`(T+2.4)K`

`(T-2.4)K`

`(T+4)K`

`(T-4)K`

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Verified by Experts

The correct Answer is:

`W_("adiabatic") = (nR(T_(1)-T_(2)))/(gamma-1) = 6R`
`implies (1xxR(T_(1)-T_(2)))/(5//3-1) = 6R implies T_(2) = (T-4)K`

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