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Suppose 0.5 mole of an ideal gas undergo...

Suppose `0.5` mole of an ideal gas undergoes an isothermal expansion an energy is added to it as heat `Q`.
Graph shows the final volume `V_(1)` versus `Q`. The temperature of the gas is (use `ln 9 = 2` and `R=25//3 J//mol-K`)

A

`293K`

B

`360K`

C

`386K`

D

`412K`

Text Solution

Verified by Experts

The correct Answer is:
B
` Q = W = nRT ln"(V_(f))/(V_(t))`
`T = (Q)/(nRlnV_(f)//V_(t)) = (1500)/(0.5 xx 25//3 xx ln3)`
=`(1500)/(0.5 xx 25//3 xx1) = 360K`
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