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In a mercury-glass thermometer the cross...

In a mercury-glass thermometer the cross-section of the capillary portion is `A_(0)` and the volume of the bulb is `V_(0)` at `273K`. If `alpha` and `gamma` are the coefficients of linear and cubical expansion coefficients of glass and mercury respectively then length of mercury in the capillary at temperature `t^(@)C` is (Ignore the increase in cross-sectional area of capillary)

A

`(V_(0))/(A_(0))(gamma - 3alpha)t`

B

`(V_(0))/(A_(0))(2gamma - 3alpha)t`

C

`(V_(0))/(A_(0))(gamma - 3alpha)(t+273)`

D

`(V_(0) gammat)/(A_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
`l= (DeltaV)/(A_(0)) = (V_(0)(gamma-3alpha)t)/(A_(0))`
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