The work done in compressing 1 kg-mol of a gas adiabatically is 146 kJ. In this process, the temperature of the gas increases by `7^@C`. The gas is : (R = 8.3 J/mol-K)

Options

A. diatomic
B. triatomic
C. A mixture of monoatomic and diatomic
D. monoatomic

Answer

A

Explanation

Work done in adiabatic process `W = (muR(T_(1)-T_(2)))/(gamma-1) implies gamma = 1 + (R(T_(2) -T_(1)))/(W)`
=`1 + (10^(3) xx 8.3(7))/(146 xx 10^(3)) = 1 + 0.40 = 1.40`
`therefore ` The gas must be diatomic