An ideal gas is initially at temperature T and volume V. ITS volume is increased by `DeltaV` due to an increase in temperature `DeltaT`, pressure remaining constant. The quantity `delta = DeltaV//V DeltaT` varies with temperature as

Options

A.
B.
C.
D.

Answer

C

Explanation

As `P` = constant so `PDeltaV = nRDeltaT implies delta = (DeltaV)/(VDeltaT) = (nR)/(PV) = (1)/(T)`