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Water of volume 2 litre in a container i...

Water of volume 2 litre in a container is heated with a coil of `1kW` at `27^@C.` The lid of the container is open and energy dissipates at rate of `160J//s.` In how much time temperature will rise from `27^@C to 77^@C` Given specific heat of water is
`[4.2kJ//kg`]

A

`8 "min" 20s`

B

`6"min" 2s`

C

`7 "min"`

D

`14"min"`

Text Solution

Verified by Experts

The correct Answer is:
A
Net heat absorbed by water `= 1000 -160 = 840J//s`
`(Q)/(t) = ("ms"DeltaT)/(t)`
`840 = (2 xx 4200 xx (77-27))/(t)`
`implies t = 500 s = 8 "min" 20s`
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